(a^2+5a-9)+a=a(7a-2)+13

Solution for (a^2+5a-9)+a=a(7a-2)+13 equation:

(a^2+5a-9)+a=a(7a-2)+13

We move all terms to the left:

(a^2+5a-9)+a-(a(7a-2)+13)=0

We add all the numbers together, and all the variables

a+(a^2+5a-9)-(a(7a-2)+13)=0

We get rid of parentheses

a^2+a+5a-(a(7a-2)+13)-9=0


We calculate terms in parentheses: -(a(7a-2)+13), so:

a(7a-2)+13

We multiply parentheses

7a^2-2a+13

Back to the equation:

-(7a^2-2a+13)


We add all the numbers together, and all the variables

a^2+6a-(7a^2-2a+13)-9=0

We get rid of parentheses

a^2-7a^2+6a+2a-13-9=0

We add all the numbers together, and all the variables

-6a^2+8a-22=0

a = -6; b = 8; c = -22;
Δ = b2-4ac
Δ = 82-4·(-6)·(-22)
Δ = -464
Delta is less than zero, so there is no solution for the equation